Ganchrow wrote
For example if a player risks $1,000 on Matchbook (accepting) at -1000 does that mean he's actually risking $1,011.11 to win $100? Or does it mean that he's risking $1,000 to win $98.90?
Well guess what? We're talking 6 of one and half a dozen of the other. Both bets are at odds of -1011.11. Same prices, just different accounting procedures.
I understand that the odds one receives for making the bet are the same whether the calculation of these odds is carried out either way. I believe the question is
If one risks $1000 at -1000 (in other words accepts an offer at -1000) starting with a balance X what is the resulting balance (assuming no other bets or offers) if one loses and what is the resulting balance if one wins.
By just reading your example one does not know whether "accepting a -1000 offer for $1000" will result in a $1000 or a $1011.11 reduction in one's balance in case of the bet losing.
For example if a player risks $1,000 on Matchbook (accepting) at -1000 does that mean he's actually risking $1,011.11 to win $100? Or does it mean that he's risking $1,000 to win $98.90?
Well guess what? We're talking 6 of one and half a dozen of the other. Both bets are at odds of -1011.11. Same prices, just different accounting procedures.
I understand that the odds one receives for making the bet are the same whether the calculation of these odds is carried out either way. I believe the question is
If one risks $1000 at -1000 (in other words accepts an offer at -1000) starting with a balance X what is the resulting balance (assuming no other bets or offers) if one loses and what is the resulting balance if one wins.
By just reading your example one does not know whether "accepting a -1000 offer for $1000" will result in a $1000 or a $1011.11 reduction in one's balance in case of the bet losing.