Math guys¦ What are the actual odds of hitting 9 consecutive -110 bets?

[Jerm3462]

9 bets in a row, all -110s.

Odds of doing this????

[ehp6737]

512-1. you calculate it 2 to the 9th power

[blackbeSSt]

depends on the sport. too many fukk ups and unknowns to get a actual %

[ehp6737]

depends on the sport. too many fukk ups and unknowns to get a actual %

He stated -110 games, so basically implying you have a 50-50% chance of winning each matchup.

Again the answer (in a vacuum) is 512-1

[bigloser]

Error

[bigloser]

again the answer (in a vacuum) is 512-1

511-1

[UpInsmoke33]

511-1 assuming you picked randomly

[bigloser]

512-1 assuming you picked randomly

511-1

[ehp6737]

511-1

Not that anyone cares whether it's 511-1 or 512-1, but it's 512-1. It's not possible to have an odd number as your answer in this equation.

[bigloser]

It's 511-1 (511 to 1) or one in 512 NOT 512-1 (512 to 1)

[ehp6737]

It's 511-1 (511 to 1) or one in 512 NOT 512-1 (512 to 1)

[Chimneyfish]

Maybe it would help if you explained your reasoning instead of just repeating it.

[bigloser]

Maybe it would help if you explained your reasoning instead of just repeating it.

I thought it was just a typo that would just be corrected when they realized they were wrong EHP still seems to think he is right.
Upinsmoke changed his post

[warriorfan707]

The odds are not the same for everyone. I love how people like to act like it is all random, like flipping a coin.

We decide what side to take... it is not handed to us. Not sure why noone understands this.

[Rod Tidwell]

.19%

[Rich Boy]

0.5^9 = .001953 = .1953%= 1 in 512 chance

[Blax0r]

It's 511-1 (511 to 1) or one in 512 NOT 512-1 (512 to 1)

This is right.

saying 512-1 for 9 bets is the same as saying that the actual odds of one -110 bet is 2-1.

[JohnGalt2341]

My best is 11 Wins in a row. I did it earlier this year. After the 11th win I figured I was some kind of genius. 2 months later I lost 11 games in a row.

[neverstoppers23]

I had won 7 in a row on covers survivor pool. Just lost today with the under on Wisconsin. Was really looking forward to my free hat with my 9th pick

[lemart5]

600-1

[FourLengthsClear]

It is 1 in 512 if you assume each bet is a 50/50 proposition
It is 1 in 337 if -110 represents the fair (no-vig) line.
It is 1 in 5000 if you are Lazy-Man

[ehp6737]

It is 1 in 512 if you assume each bet is a 50/50 proposition
It is 1 in 337 if -110 represents the fair (no-vig) line.
It is 1 in 5000 50000 if you are Lazy-Man

Fixed

[NYSportsGuy210]

It can be done....once again a combination of due diligence, patience and luck all have to go your way. SOme can do it in a week others in a few weeks or even a few months. Not easy however.

[mcbaseball10]

The odds are the same as losing 9 in a row.

[samserif]

The odds are the same as losing 9 in a row.

The only difference is that 9 wins in a row are always due to skill whereas 9 losses in a row are always due to bad luck.

[InTheDrink]

ehp might be the smartest poster on the board so I trust 512. Even if he is a prikk

[passurchipz619]

512 to 1??? BRiNG IT ON! the key is don't feel pressured to bet everyday...sounds like a no brainer but when the dubs start rolling its hard to lay off plays..

[InTheDrink]

Correct me if I'm wrong but this is for a series of 9 bets 512 times. So you'd Have to make 4500+ bets to win 9 in a row

[mrmarket]

better odds than lotto bet those parlays men. stay in action.

[Inkwell77]

335.852 to 1 on 9 -110 bets.
So you bet a $10 nine teamer and you would profit $3,358.52 and the sportsbook would pay you a total of 3,368.52 (if they were to give out pennies and pay true odds). For anyone wondering how to calculate parlays with various juice here is my simple version (just for - amounts, calculating a parlay with a dog is a little different, not much)
100/110 = .90909
You then add 1 to that previous amount.
So you have 1.90909
Now for 9 bets you multiply
1.90909 *1.90909 * 1.90909.... etc
You will come out to an amount of 336.852
Then take that 336.852 and multiply it by the amount you would like to bet ($10 * 336.852)
Then subtract the original amount bet to find your profit ($3,368.52 - $10 = $3,358.52)



The Hilton caps off any parlay at 300-1 so if you are a parlay guy never any reason to put in a parlay that pays more than 300-1 at the Hilton. Not really sure if any other book in Vegas has a cap. Online is way different.

[RudyRuetigger]

[FourLengthsClear]

Correct me if I'm wrong but this is for a series of 9 bets 512 times. So you'd Have to make 4500+ bets to win 9 in a row

No that isn't right.

Your logic is right only if applied to 512 9 team parlays. You would expect to win only one of those (assuming a 50/50 distribution).

[ehp6737]

335.852 to 1 on 9 -110 bets.
So you bet a $10 nine teamer and you would profit $3,358.52 and the sportsbook would pay you a total of 3,368.52 (if they were to give out pennies and pay true odds). For anyone wondering how to calculate parlays with various juice here is my simple version (just for - amounts, calculating a parlay with a dog is a little different, not much)
100/110 = .90909
You then add 1 to that previous amount.
So you have 1.90909
Now for 9 bets you multiply
1.90909 *1.90909 * 1.90909.... etc
You will come out to an amount of 336.852
Then take that 336.852 and multiply it by the amount you would like to bet ($10 * 336.852)
Then subtract the original amount bet to find your profit ($3,368.52 - $10 = $3,358.52)



The Hilton caps off any parlay at 300-1 so if you are a parlay guy never any reason to put in a parlay that pays more than 300-1 at the Hilton. Not really sure if any other book in Vegas has a cap. Online is way different.

What the book uses to calculate parlay payouts and the actual mathematical odds are two different things. I dont believe OP was asking about the books payout, but rather the actual odds which are 1 out of 512.

[donjuan]

LOL at the guy insisting that it's 512-1. I guess the odds of winning 2 flips in a row is 4-1 in your bizarro world?

[The Kraken]

It's impossible... which also equals about .19%