searching for arbs

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  • superjeff24
    SBR MVP
    • 03-17-10
    • 1078

    #1
    searching for arbs
    ok, I'm not sure how many people will want to help me with this, but I have trouble understanding the formulas for finding whether a bet is an arb or not. I have found an arb calculator and I have no idea how to work it. Normally my math isn't this bad, but for some reason it doesn't compute.
    Something about there needs to be a difference of less than 100% however that works out?

    Anyways, if anyone here has the patience to break this down so that a dummy (me) can grasp it, I would be much obliged.
  • Dunder
    Restricted User
    • 10-26-09
    • 3345

    #2
    When using US odds (in two-way events) it is really simple. Suppose the best odds there are for Team A is -200. To be an arb the other side has to be better than +200. To convert to percentages is also easy.

    -200 as a percentage is 200 divided by 200+100 or 66.67%
    +200 as a percentage is 100 divided by 200+100 or 33.33%

    In the case of a genuine arb say -110 and +120, this same formula applies i.e.

    -110 as a percentage is 110 divided by 110+100 = 52.38%
    +120 as a percentage is 100 divided by 120+100 = 45.45%
    In this case the total of 97.83% means that the books would pay you $100 for every $97.83 you stake.
    Last edited by Dunder; 03-22-10, 04:49 PM.
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    • superjeff24
      SBR MVP
      • 03-17-10
      • 1078

      #3
      ok, so the books cant be (-110) and (+110) then?
      Comment
      • Dunder
        Restricted User
        • 10-26-09
        • 3345

        #4
        Originally posted by superjeff24
        ok, so the books cant be (-110) and (+110) then?
        That would be a break even proposition for you.
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        • superjeff24
          SBR MVP
          • 03-17-10
          • 1078

          #5
          ok, if I understand (-140) and (+120) would be arbable because:

          100 divided by 140+100=41.67% and
          100 divided by 120+100=45.45% being under 100% total?
          Comment
          • Dunder
            Restricted User
            • 10-26-09
            • 3345

            #6
            Originally posted by superjeff24
            ok, if I understand (-140) and (+120) would be arbable because:

            100 divided by 140+100=41.67% and
            100 divided by 120+100=45.45% being under 100% total?
            No. This is not an arb.

            -140 as a percentage is 140 divided by 140+100 = 58.33%

            for odds better than +100 the numerator is 100
            for odds worse than +100 the numerator is the based on the odds.
            Comment
            • superjeff24
              SBR MVP
              • 03-17-10
              • 1078

              #7
              thanks alot for your help. now to find some!
              Comment
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