Please Help I do not understand Round Robin

rookie · 03-25-10, 01:38 PM

Originally posted by as99

I've read the other topics on this forum and searched the net but I still do not have a clue. I have used the calculator and still do not understand it.

I do not understand the terminology that is being used.

Can somebody simplify in "DUMMIES" terms.

Here's an example: MMA:

4 MATCHES:

I picked the winners:
-140
+110
-165
-115

I enter $1 for the following bets:

I select Round Robin's with 2's: $6.00 To Win $13.86

2's & 3's: $10.00 To Win $33.82

3's & 4's: $11.00 To Win $43.63

3's: $4.00 To Win $19.97

3's & 4's: $5.00 To Win $29.77

I do not understand this. What does this mean? I have to get 3 correct prediction's for 3's?

There are 4 separate $1 parlay bets - each consisting of 3 teams/fighters etc: ABC, ACD, BCD, ABD.

In case you don't know, a parlay bet means you have to win all the individual bets to win the whole bet.

Somebody please clarify this in simple terms. Like how many predictions do I have to get right.

For example: 2's & 3's: $10.00 To Win $33.82. What would have to happen in my 4 predictions to get this.

2's and 3's : 6 separate $1 parlay bets - each consisting of 2 teams/fighters etc ( AB, AC, AD, BC, BD, CD) and 4 separate $1 parlay bets - each consisting of 3 teams/fighters etc(ABC, ACD, BCD, ABD)

If anyone can explain using my 4 predictions that would help.

THANK YOU for your time.

My response is in bold.

as99 · 03-25-10, 01:44 PM

Thank you for your reply.

So how many parlay bets do I have to get right to win? For example I understand how 3's = 4 separate $1 bet. Would I have to get 3 right for 3's?

What about when 2 numbers are involved like 2's and 3's. How many PARLAYS do I have to get then? Since it turns into 10 parlays.

Chi_archie · 03-25-10, 01:46 PM

it depends on the odds of each individual parlay as99

since you used different odds for your four legs of the round robin each parlay will be a bit different.

you can plug the individual numbers in here....

http://www.sbrforum.com/Betting+Tools/Parlay+Calculator.aspx

as99 · 03-25-10, 01:51 PM

Yes thanks, I understand that part. That odds are always different.

Now that I understand the terminology behind the bet. The only question I have is how many correct parlays do I need to win?

For example 3's = 4 PARLAYS. For 2's & 3's = 10 PARLAYS.

How many do I need right to win?

rookie · 03-25-10, 01:59 PM

Originally posted by as99

Thank you for your reply.

So how many parlay bets do I have to get right to win? For example I understand how 3's = 4 separate $1 bet. Would I have to get 3 right for 3's?

What about when 2 numbers are involved like 2's and 3's. How many PARLAYS do I have to get then? Since it turns into 10 parlays.

The $ win amount you see displayed on the bookie's site is the maximum winnings if you win ALL your parlay bets.

In case of 3's, you have to get at least 3 selections right to win at least one parlay and if you get 4 right, you will win all four parlays.

Similar is the case for 2's and 3's: You get A and D right, you win one AD parlay and lose remaining 9. If you get A, B, D right you will win AB, AD, BD and ABD parlays and lose remaining 6.

If you want to know more, google permutation and combination.

Chi_archie · 03-25-10, 02:14 PM

well basically to make it simple for you.... if you don't have 3 teams win..... you're gonna lose alot

don't do round robins with 4 teams... you gotta hit 75% to make $

paco · 03-25-10, 02:18 PM

Keep it simple and only bet straight bets if u wanna last in this game.