Which way will leave me with the most money???

[ohdear]

1. Blindly betting 1,000 -110 spreads
    
2. Blindly betting 1,000 +140 ML's on a (+140/-160 line)
    
3. Blindly betting 1,000 -160 ML's on a (+140/-160 line)
    
4. Blindly betting 1,000 +750 ML's on a (+750/-1000 line)
    
5. Blindly betting 1,000 -1000 ML's on a (+750/-1000 line)

If I start with a $10,000 bankroll in all independent cases, and bet $10 on every game, what is my expected loss on all of these? Obviously I will expect to lose money in ALL cases, but betting which one would kill me the most?

[Peep]

Should be easy to figure out.

Are you betting your $10 on the dog or the favorite, or on both?

[Pancho sanza]

Are you betting 10 bucks no matter which option you take?

if thats the case, and assuming the prices are perfect and the vig is spread equally over the dog/fav, would have to be either +750 or -1000 since that straddle has least the least vig.

[TomG]

In order from highest ending bankroll to lowest ending bankroll...

E, C, D, B, A

I will also accept E, D, C, B, A as correct.

[u21c3f6]

A. $9,545
B & C $9,689
D & E $9,740

Balance of bankroll after 1,000 $10 wagers.

Joe.

[ohdear]

Thanks everyone but how do you come up with these #'s?? Can someone type out the equations you did?

[Ganchrow]

Thanks everyone but how do you come up with these #'s?? Can someone type out the equations you did?

See:

http://forum.sbrforum.com/handicappe...rcentages.html

-and-

http://forum.sbrforum.com/handicappe...ical-hold.html