ok so i was mulling over carib and looking at there contest, they have a pick 10 contest which is a 20 dollar entry fee in which you select 10 games ATS and if a contestant either goes 10-0(20 points) or has the most points after 10 picks is declared a 5,000 dollar winner, like wise if any contestant goes 0-10 hes deemed the biggest loser and is awarded 5,000. how many multiple accounts would be needed to play both sides and guarentee you to loose 10 in a row. I think its obviously more than 5,000 since they offer this
Can this be statistically beaten
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UntilTheNDofTimESBR Hall of Famer
- 05-29-08
- 9283
#1Can this be statistically beatenTags: None -
u21c3f6SBR Wise Guy
- 01-17-09
- 790
#2There would be 2^10 or 1,024 different accounts needed. At $20 per that would be $20,480. Of course you would have both the 0-10 and the 10-0 accounts.Comment -
UntilTheNDofTimESBR Hall of Famer
- 05-29-08
- 9283
#3thought so , thanksComment
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