[Actionbrett]

A while ago someone had an article regarding the odds of losing an 'x' amount of games in a row in Football, both pro and college combined and was wondering if anyone had an answer or guesstimate to my question below.

I have an action account at betphoenix and use the money in that account to follow a few good services that have won me some money over a good period of time. Today capped off a 1-15-1 run the past 20 days. I could blindly do better and we were wondering how mathematically this is very very tough to do. 14 of those loses were in a row. Anyone know what the odds are of pulling off this feat?

[Unitage]

this is basically a 14 team parlay so i checked out the parlay calculator at sbr and duno if this is right but at EVEN +100 odds per game, $100 would net
Mathematical Odds: +1638300 True Parlay Odds: +1638300 True Parlay
Win Amount: $1,638,300.00 Premium Paid Over
Mathematical Odds: 99.99% Premium Paid Over
True Parlay Odds: 99.99%

[Flight]

Assuming that you are playing 'even' wagers, that is -110/-110 on each side, there is 50% chance of winning each wager. Therefore to lose 2 in a row you have:

p= (0.5)(0.5) = 0.25

To lose 3 in a row you have:

p = (0.5)(0.5)(0.5) = 0.125 = 1/8

And so on... let x be the number of times you lose a wager (or win for that matter)

p = (odds)^x

So for 14 games in a row:

p = (0.5)^14
= 0.00006103515625

Which is 1/16384

[Actionbrett]

So for 14 games in a row:

p = (0.5)^14
= 0.00006103515625

Which is 1/16384

Glad i can hit those odds, Thanks bud.

[SR]

I have just about gone insane when i was incorrect on 6 in a row, 14 would probably have me quitting for awhile.

[blix177]

Next time you hit 5 in a roll wrong, buy both team for the 6th game and make sure you make it a 1/2 pointer so it wont tie.

[juuso]

Next time you hit 5 in a roll wrong, buy both team for the 6th game and make sure you make it a 1/2 pointer so it wont tie.

What's the point of doing that?

[poker_dummy101]

What's the point of doing that?

uhh so he wins 1. it was a joke?