adjusted odds

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  • Buffalo Nickle
    SBR MVP
    • 11-12-14
    • 3228

    #1
    adjusted odds
    Here's a question for the math and spreadsheet proficient. Assuming a 50% coinflipper deposits $1,000 and gets a 100% free play, what are his adjusted odds if he bets 1.1% per bet at -110 odds to meet a 20x rollover on the deposit amount?

    Similar scenario. What are the adjusted odds betting at -107 odds and depositing $1,000 and getting a $100% cash bonus if he bets 1.1% to meet a 36x rollover of the deposit amount?

    Thanks for any help.
    Last edited by Buffalo Nickle; 05-01-15, 10:52 AM.
  • chunk
    SBR Wise Guy
    • 02-08-11
    • 808

    #2
    Originally posted by Buffalo Nickle
    Here's a question for the math and spreadsheet proficient. Assuming a 50% coinflipper deposits $1,000 and gets a 100% free play, what are his adjusted odds if he bets 1.1% per bet at -110 odds to meet a 20x rollover on the deposit amount?

    Similar scenario. What are the adjusted odds betting at -107 odds and depositing $1,000 and getting a $100% cash bonus if he bets 1.1% to meet a 36x rollover of the deposit amount?

    Thanks for any help.
    Nice math questions....what is your definition of spread sheet proficient?
    Comment
    • u21c3f6
      SBR Wise Guy
      • 01-17-09
      • 790

      #3
      I am not sure how to answer your specific questions but here is how I would look at it.

      In the first scenario you have to wager $20,000. $20,000/$11 wagers = approx 1,818.182 wagers of which you would win approx 909.0909 and lose 909.0909. Therefore you would win 9,090.91 on your winning wagers (10 x 909.0909) and lose 10,000 on your losers (11 x 909.0909) for a net loss of 909.09 to win a $1,000 free play.

      In scenario 2 I will change it slightly to wager $10.70 instead of 1.1%. In this scenario you have to wager $36,000. $36,000/$10.70 wagers = approx 3,364.486 wagers of which you would win approx 1,682.243 and lose 1,682.243. Therefore you would win 16,822.43 on your winning wagers (10 x 1,682.243) and lose 18,000 on your losers (10.70 x 1,682.243) for a net loss of 1,177.57 to win a $1,000 cash bonus.

      Hope that helps. Joe.
      Comment
      • Buffalo Nickle
        SBR MVP
        • 11-12-14
        • 3228

        #4
        Originally posted by u21c3f6
        I am not sure how to answer your specific questions but here is how I would look at it.

        In the first scenario you have to wager $20,000. $20,000/$11 wagers = approx 1,818.182 wagers of which you would win approx 909.0909 and lose 909.0909. Therefore you would win 9,090.91 on your winning wagers (10 x 909.0909) and lose 10,000 on your losers (11 x 909.0909) for a net loss of 909.09 to win a $1,000 free play.

        In scenario 2 I will change it slightly to wager $10.70 instead of 1.1%. In this scenario you have to wager $36,000. $36,000/$10.70 wagers = approx 3,364.486 wagers of which you would win approx 1,682.243 and lose 1,682.243. Therefore you would win 16,822.43 on your winning wagers (10 x 1,682.243) and lose 18,000 on your losers (10.70 x 1,682.243) for a net loss of 1,177.57 to win a $1,000 cash bonus.

        Hope that helps. Joe.
        Thanks for the info. I had done similar calculation to determine the value of the bonuses I have taken so at least I know I didn't get cross-eyed. I just wanted to try to get the odds pinned down for the sake of comparison which would make it easy to determine the value of other bonuses as well.
        Comment
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