Simple roulette system RNG (Daily Video Series) Will it fail???
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RunebladeSBR MVP
- 09-29-17
- 2579
#71Comment -
jjgoldSBR Aristocracy
- 07-20-05
- 388189
#75Has anybody tried thisComment -
RunebladeSBR MVP
- 09-29-17
- 2579
#76Ill tell ya what, If I double my bankroll then Ill stop and I will be done with the thread. Cool?Comment -
jjgoldSBR Aristocracy
- 07-20-05
- 388189
#77You got to keep the thread going to see what happensComment -
Pete0SBR MVP
- 04-09-10
- 3849
#79
player edge and house edge is the exact same on every single bet.
Also applies to sports.
can any1 please confirm this ?
the myth of "long term, the house always wins"
house wins since bet #1, when lines are -110 , when 0 exists on the wheel
whether it be bet#1 or Bet#284Comment -
RunebladeSBR MVP
- 09-29-17
- 2579
#81disagree.
player edge and house edge is the exact same on every single bet.
Also applies to sports.
can any1 please confirm this ?
the myth of "long term, the house always wins"
house wins since bet #1, when lines are -110 , when 0 exists on the wheel
whether it be bet#1 or Bet#284Comment -
Mike HuntertzSBR Posting Legend
- 08-19-09
- 11204
#82disagree.
player edge and house edge is the exact same on every single bet.
Also applies to sports.
can any1 please confirm this ?
the myth of "long term, the house always wins"
house wins since bet #1, when lines are -110 , when 0 exists on the wheel
whether it be bet#1 or Bet#284Comment -
Pete0SBR MVP
- 04-09-10
- 3849
#83You are correct. No 0 would be 50%. Those are the odds of hitting red or black. Probability is different from odds though. Basically I'm using a permutation to win bets. Your challenging the wheel to match or mismatch the exact permutation or pattern that just came out and that is where cumulative probability comes in. You can never change the odds but you can change the probability of winning. After all, why do casinos have table limits?
i see.
limits are there as a combination of risk management (such as this strategy) and other things as well, i presumeComment -
lonegambler23SBR Hall of Famer
- 06-22-16
- 9761
#84jewlette will always get u in the endComment -
RunebladeSBR MVP
- 09-29-17
- 2579
#85
Your talking 12 steps. If I wait for 4 triggers and then bet that then the casino would have to match an exact pattern of 16 to beat me which would be a probability of 1 and 97000 spins. Goodluck beating me that's all I can say. A loss is always possible of course but with that probability, it would be awfully difficult to lose.
With that being said it does does seem silly to risk 51K to win $25....lolComment -
unclebuzz1SBR Wise Guy
- 08-23-09
- 565
#86Think of an 8 team parlay. 2 to the 8th possible outcomes = 256. Only 1 combination is a winner with 255 losers. You're betting the reverse. 255 possible winning combinations with 1 loser. You should expect to lose 1 out of every 256 (actual) bets. This doesn't mean you'll lose once in the 1st 256 bets but maybe twice in 512 bets, 3X in 768 bets, or 4X in 1024 bets. These are at even money bets. At negative odds, you eventually run out of money. Have fun while it lasts!Comment -
unclebuzz1SBR Wise Guy
- 08-23-09
- 565
#88Let's say for example I'm a whale and I go into a casino with $500,000 and I go up to a table with no limits. I could do a bet spread of 25-50-100-200-400-800-1600-3200-6400-12800-25600-51200 right?
Your talking 12 steps. If I wait for 4 triggers and then bet that then the casino would have to match an exact pattern of 16 to beat me which would be a probability of 1 and 97000 spins. Goodluck beating me that's all I can say. A loss is always possible of course but with that probability, it would be awfully difficult to lose.
With that being said it does does seem silly to risk 51K to win $25....lol
If only this were true! A sequence of 12 bets will have 2 to the 12th power possible outcomes = 4,096. You can expect to lose once in 4,096 bets, etc.Comment -
RunebladeSBR MVP
- 09-29-17
- 2579
#90Day 4 I almost bit the dust on this one.
<iframe width="560" height="315" src="https://www.youtube.com/embed/V_TXlFwq2BU" title="YouTube video player" frameborder="0" allow="accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture" allowfullscreen></iframe>Comment -
BeatTheJerkBARRELED IN @ SBR!
- 08-19-07
- 31794
#91Day 4 I almost bit the dust on this one.
<iframe width="560" height="315" src="https://www.youtube.com/embed/V_TXlFwq2BU" title="YouTube video player" frameborder="0" allow="accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture" allowfullscreen></iframe>Comment -
texhooperSBR Posting Legend
- 01-05-09
- 10001
#93Operative word being die
Invest this money wisely away from crypto while you have it friendComment -
newton0038SBR MVP
- 03-07-07
- 2379
#94disagree.
player edge and house edge is the exact same on every single bet.
Also applies to sports.
can any1 please confirm this ?
the myth of "long term, the house always wins"
house wins since bet #1, when lines are -110 , when 0 exists on the wheel
whether it be bet#1 or Bet#284
The whole theory that the house always wins long term is the fact that the HOUSE isn't human. The house is in control of its risk. The house doesn't sleep, eat, shit or fuk and the only influence it has is volume which can be adjusted accordingly( i.e. line moves, vig moves, slot machine floor layout, firing dealers that expose their hole card...etc) Mind you I'm talking about a professionally managed land based business.
As for the roulette, there are 37 possible outcomes on a single zero wheel. Payoff is 35-1 on a #. try the cover all numbers except 2 numbers of your choice either it be random or evidence based. You will make 1 unit on each spin with the exception if 1 of the 2 numbers left open hit then you say " who the fuk ever came up with this system.Comment -
BeatTheJerkBARRELED IN @ SBR!
- 08-19-07
- 31794
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juicernameSBR Hall of Famer
- 10-14-15
- 6906
#98Why would it be any different if you start your next session 1 second later, 10 min later, 12 hours later or the next day? The math is still the same.Comment -
BeatTheJerkBARRELED IN @ SBR!
- 08-19-07
- 31794
#99Where’s our fuckin’ video today palComment -
unclebuzz1SBR Wise Guy
- 08-23-09
- 565
#101
You are correct! The math is the same EVERYWHERE!!
The math is the same for all 256 random patterns of 8 steps. (This is calculated as 2 to the 8th power = 256).
RRRRRRRR is one of those random patterns. He may as well be using ALL REDS for his random pattern, every time, and stop wasting time establishing a new random pattern, every time.
For 255 of those patterns, you win $1 for every (actual) bet made (regardless of whether it wins or loses) plus the amount placed on the winning bet.
For 1 of those patterns, you lose $502 (1+3+7+15+31+63+127+255 = $502)
At even odds, the break even point is 256 bets. (You aren't getting even odds here.)
Beyond that, the only question is whether that single loss comes before the 256th bet or doesn't come at all during this series of 256 bets.
If it comes before the 256th bet then you've lost more money than you've made in this series and your current bankroll will be less than when this series started. (If it happens in the 1st series, your current bankroll will be less than your original bankroll.)
If you win all 256 bets, it doesn't mean it's a winning system. It means you've won enough to cover 1 loss in the next series of 256 bets.
Eventually, the law of averages will catch up and you'll have more than 1 loss in a series.
Have fun while it lasts but this is nothing more than an aggressive martingale system with a unique method of placing bets!Last edited by unclebuzz1; 10-30-21, 04:29 PM.Comment -
DiggityDaggityDoSBR Aristocracy
- 11-30-08
- 81454
#102Uncle BuzzkillComment -
unclebuzz1SBR Wise Guy
- 08-23-09
- 565
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JacketFan81SBR MVP
- 10-28-17
- 1743
#104
You are correct! The math is the same EVERYWHERE!!
The math is the same for all 256 random patterns of 8 steps. (This is calculated as 2 to the 8th power = 256).
RRRRRRRR is one of those random patterns. He may as well be using ALL REDS for his random pattern, every time, and stop wasting time establishing a new random pattern, every time.
For 255 of those patterns, you win $1 for every (actual) bet made (regardless of whether it wins or loses) plus the amount placed on the winning bet.
For 1 of those patterns, you lose $502 (1+3+7+15+31+63+127+255 = $502)
At even odds, the break even point is 256 bets. (You aren't getting even odds here.)
Beyond that, the only question is whether that single loss comes before the 256th bet or doesn't come at all during this series of 256 bets.
If it comes before the 256th bet then you've lost more money than you've made in this series and your current bankroll will be less than when this series started. (If it happens in the 1st series, your current bankroll will be less than your original bankroll.)
If you win all 256 bets, it doesn't mean it's a winning system. It means you've won enough to cover 1 loss in the next series of 256 bets.
Eventually, the law of averages will catch up and you'll have more than 1 loss in a series.
Have fun while it lasts but this is nothing more than an aggressive martingale system with a unique method of placing bets!Comment -
RunebladeSBR MVP
- 09-29-17
- 2579
#105
You are correct! The math is the same EVERYWHERE!!
The math is the same for all 256 random patterns of 8 steps. (This is calculated as 2 to the 8th power = 256).
RRRRRRRR is one of those random patterns. He may as well be using ALL REDS for his random pattern, every time, and stop wasting time establishing a new random pattern, every time.
For 255 of those patterns, you win $1 for every (actual) bet made (regardless of whether it wins or loses) plus the amount placed on the winning bet.
For 1 of those patterns, you lose $502 (1+3+7+15+31+63+127+255 = $502)
At even odds, the break even point is 256 bets. (You aren't getting even odds here.)
Beyond that, the only question is whether that single loss comes before the 256th bet or doesn't come at all during this series of 256 bets.
If it comes before the 256th bet then you've lost more money than you've made in this series and your current bankroll will be less than when this series started. (If it happens in the 1st series, your current bankroll will be less than your original bankroll.)
If you win all 256 bets, it doesn't mean it's a winning system. It means you've won enough to cover 1 loss in the next series of 256 bets.
Eventually, the law of averages will catch up and you'll have more than 1 loss in a series.
Have fun while it lasts but this is nothing more than an aggressive martingale system with a unique method of placing bets!Comment
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