1. #1
    Big Odds
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    Help

    Hello,

    I need your help. Can anyone add numbers for 11 selections? Thank you.


  2. #2
    SBR Genie
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    Hi Big Odds,

    I'll slink this thread to "Handicapper Think Tank" forum to get more replies.
    Nomination(s):
    This post was nominated 1 time . To view the nominated thread please click here. People who nominated: SilverSpoon111

  3. #3
    HeeeHAWWWW
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    The answer for each box = add the number to the left, to the number left and up a row.

  4. #4
    danshan11
    I am good at coin flips, I really am!
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    11 is
    55
    165
    330
    462
    330
    165
    11

  5. #5
    danshan11
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    sorry i missed 55

  6. #6
    semibluff
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    Quote Originally Posted by Big Odds View Post
    Hello,

    I need your help. Can anyone add numbers for 11 selections? Thank you.

    @danshan11 has already provided you with the answer. I can provide you with the math and an explanation.
    For singles the answer is N, where N is the total numbers of selections. Each selection can be picked on its own. From a Math perspective the equation is N / 1.
    For Doubles the answer is N * (N - 1) / (1 * 2) or N squared minus M, all divided by 2. With 11 selections each of them can be paired with the other 10 so that would be 11 * 10. This gives you Combination A * B and B * A, which is the same thing, hence every combination is repeated so it has to be divided by 2.
    For Trebles the answer is N * (N - 1) * (N - 2) / (1 * 2 * 3). With 11 selections each of them can be paired with the other 10 so that would be 11 * 10. Each of those doubles can be paired with the other 9 selections to make Trebles. That's where the 11 * 10 * 9 comes in. Each double is repeated twice and each Treble is repeated 3 times which is where the 1 * 2 * 3 comes in. A * B is the same as B * A and for trebles A * B * C is the same as A * C * B and C * A * B. Switch the A and B around for the other 3.
    For 4-folds the answer is N * (N - 1) * (N - 2) * (N - 3) / (1 * 2 * 3 * 4). Hopefully you can see the pattern forming for all the other possible combinations.
    If you had 100 the doubles would 100 * 99 / 2. Trebles would be 100 * 99 * 98 / (2 * 3). 4-folds would be 100 * 99 * 98 * 97 / (2 * 3 * 4). 5-folds would be 100 * 99 * 98 * 97 * 96 / (2 * 3 * 4 * 5).

    For anyone interested counting a string of numbers from 1 to 'whatever' works in a similar way. Counting 1 to 100 can be done as 1 + 2 + 3...all the way to 100. It can also be done as 100 + 99 + 98...all the way back to 1. Visually if you wrote the 1st way down on a piece of paper and then wrote the 2nd way underneath it you'd see 1 over 100, 2 over 99, 3 over 98 and so on. If you counted downwards rather than left to right you'd have 101 exactly 100 times. The math is (N + 1) * N / 2. So if you counted all the numbers from 1 to 100 you'd get 101 * 100 / 2 or 5050 for those who are really struggling.

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