Help

**SBR Genie** · 08-02-18, 11:10 AM

Hi Big Odds,

I'll slink this thread to "Handicapper Think Tank" forum to get more replies.

**HeeeHAWWWW** · 08-02-18, 11:46 AM

The answer for each box = add the number to the left, to the number left and up a row.

**danshan11** · 08-02-18, 12:09 PM

11 is
55
165
330
462
330
165
11

**danshan11** · 08-02-18, 12:10 PM

sorry i missed 55

**semibluff** · 08-03-18, 12:50 AM

Originally posted by Big Odds

Hello,

I need your help. Can anyone add numbers for 11 selections? Thank you.

@danshan11 has already provided you with the answer. I can provide you with the math and an explanation.
For singles the answer is N, where N is the total numbers of selections. Each selection can be picked on its own. From a Math perspective the equation is N / 1.
For Doubles the answer is N * (N - 1) / (1 * 2) or N squared minus M, all divided by 2. With 11 selections each of them can be paired with the other 10 so that would be 11 * 10. This gives you Combination A * B and B * A, which is the same thing, hence every combination is repeated so it has to be divided by 2.
For Trebles the answer is N * (N - 1) * (N - 2) / (1 * 2 * 3). With 11 selections each of them can be paired with the other 10 so that would be 11 * 10. Each of those doubles can be paired with the other 9 selections to make Trebles. That's where the 11 * 10 * 9 comes in. Each double is repeated twice and each Treble is repeated 3 times which is where the 1 * 2 * 3 comes in. A * B is the same as B * A and for trebles A * B * C is the same as A * C * B and C * A * B. Switch the A and B around for the other 3.
For 4-folds the answer is N * (N - 1) * (N - 2) * (N - 3) / (1 * 2 * 3 * 4). Hopefully you can see the pattern forming for all the other possible combinations.
If you had 100 the doubles would 100 * 99 / 2. Trebles would be 100 * 99 * 98 / (2 * 3). 4-folds would be 100 * 99 * 98 * 97 / (2 * 3 * 4). 5-folds would be 100 * 99 * 98 * 97 * 96 / (2 * 3 * 4 * 5).

For anyone interested counting a string of numbers from 1 to 'whatever' works in a similar way. Counting 1 to 100 can be done as 1 + 2 + 3...all the way to 100. It can also be done as 100 + 99 + 98...all the way back to 1. Visually if you wrote the 1st way down on a piece of paper and then wrote the 2nd way underneath it you'd see 1 over 100, 2 over 99, 3 over 98 and so on. If you counted downwards rather than left to right you'd have 101 exactly 100 times. The math is (N + 1) * N / 2. So if you counted all the numbers from 1 to 100 you'd get 101 * 100 / 2 or 5050 for those who are really struggling.