1. #1
    tripas for lunch
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    Join Date: 01-05-11
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    Any Math Geniuses Out There?

    Let's say a book is offering payouts on either side of an event:

    For outcome a, the payout is A (1 unit stake plus winnings)

    For outcome b, the payout is B.

    I know that the house edge is as follows:

    1/A +1/B - 1

    This makes intuitive sense, but what I am looking for someone who can demonstrate a mathematical proof of why this is so.

  2. #2
    rfr3sh
    Blind Knucklehead
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    Join Date: 11-07-09
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    For A Spread Bet I would say:

    Assuming that the line is 100% accurate then there should be a 50/50 chance that the team covers the number

    so the fair odds should be +100/+100 (50/50)
    however at -110 it is saying that there is a 52.38% chance that Team A or B covers the number
    therefore the house has a 2.38 % edge

  3. #3
    Kaabee
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    house edge on -110 is 4.55%. half the time we lose 110. half the time we win 100. so for every 220 bet we lose 10. 10/220 = .0454545

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