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Pick Six- No One Can Do It Today in NFL- Guaranteed - Go Ahead, TRY
1) Pick Winner of New England at Denver
2) Pick Winner of San Francisco at Seattle
3) Pick NE at Denver (-5 1/2) vs. the Spread
4) Pick SF at Seattle (-3 1/2) VS. THE Spread
5) Pick NE at Denver Over Under (56 1/2)
6) Pick SF at Seatlle Over Under (40)
Don't care how much you think you know or how lucky you think are.
There is no one that can Pick 6 'all correct'.
You would have more chance at the Pick 6 at Aqueduct Park.
Go ahead and give it a try fellas.
PICK 6
Den
SF
Den
SF
Over
Over
Ne
sea
ne
sf
over
under
I'll Try:
New England
Seattle
New England (+5 1/2)
San Fran (+3 1/2)
NE/Den Under
SF/Sea Over
Ne
sf
ne
sf
un
un
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Well lets not say its impossible. Unlikely w extremely low odds? Yes. Impossible? No
Denver
Seattle
Denver
Settle
Under
Under
Maybe I'll go 0 for 6 tonight
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Den
SF
Den ATS
SF ATS
Den un
SF ov
1) Denver
2) Seattle
3) Denver (-5 1/2)
4) Seattle (-3 1/2)
5) Under (56 1/2)
6) Over (40)
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Thats the winning ticket^^^Originally Posted by no1here
1) Pick Winner of New England at Denver (Denver)
2) Pick Winner of San Francisco at Seattle (SF)
3) Pick NE at Denver (-5 1/2) vs. the Spread (Denver)
4) Pick SF at Seattle (-3 1/2) VS. THE Spread (SF)
5) Pick NE at Denver Over Under (56 1/2) (Over)
6) Pick SF at Seattle Over Under (40) (Under)
Denver
Seattle
NE
Seattle
over
over
Not even close to impossible. If they were totally un correlated I believe there are 720 possible combinations, but there are less than that because there is no way a dog can win but not cover, removing a number of possible combinations. Better odds than winning lottery.
Easier than pick six because each pick 6 race has more than two horses running. These 6 have exactly two possible outcomes with the exception of Seattle total which has 3 because it could push.
Definitely not impossible.
denver
seattle
pats
SF
under
under
Denver
seattle
denver ats
niners ats
den under
sea over
newguy gets it
denver
SF
pats
SF
under
over
...1) Pick Winner of New England at Denver
2) Pick Winner of San Francisco at Seattle
3) Pick NE at Denver (-5 1/2) vs. the Spread
4) Pick SF at Seattle (-3 1/2) VS. THE Spread
5) PickNE at Denver Over Under (56 1/2)
6) Pick SF at Seatlle Over Under (40)
Don't care how much you think you know or how lucky you think are.
There is no one that can Pick 6 'all correct'.
You would have more chance at the Pick 6 at Aqueduct Park.
Go ahead and give it a try fellas.
PICK 6
1. Denver
2. San Fran
3. ehhh I guess Denver but this is the only one I'm not sure about
4. San Fran
5.Over
6. Under
Den
Sea
Den
Sea
Over
Over
Denver, San Fran, N.Eng., San Fran, Under, over1) Pick Winner of New England at Denver
2) Pick Winner of San Francisco at Seattle
3) Pick NE at Denver (-5 1/2) vs. the Spread
4) Pick SF at Seattle (-3 1/2) VS. THE Spread
5) Pick NE at Denver Over Under (56 1/2)
6) Pick SF at Seatlle Over Under (40)
Don't care how much you think you know or how lucky you think are.
There is no one that can Pick 6 'all correct'.
You would have more chance at the Pick 6 at Aqueduct Park.
Go ahead and give it a try fellas.
PICK 6
1) New England
2) Seattle
3) New England
4) San fran
5) Under
6) Over
NE
SF
NE plus points
SF plus points
NE under
SF under
Denver game and ML
san Fran game and ML
over and over
1) Denver
2) San Francisco
3) Denver (-5 1/2)
4) Pick SF (+3 1/2)
5) Under (56 1/2)
6) Over (40)
1- NE 2- SF 3-NE 4- SF 5-Under 6-Over
No one did it, as predicted.
I hope your other predictions in life work out better then this one . I am including your pathetic argument that no one picked all six because one was a push that is sure to follow.
Three of the first 6 or 7 posters picked every single wager correctly, very strong fellas.
Of course it is not impossible, if they were unrelated not factoring in pushes there are only 64 combinations. Factoring in the push there are 96 combinations.
Your horse racing example is wrong though. Because the number of horses is only a very small part of the odds. Just because there are more combinations doesn't mean something is harder or easier to predict. For instance.........
1. If you put a team of NBA all stars in the NCAA march madness field of 64 there are 64 possible outcomes regarding who will win the championship.
2. there are 30 MLB teams so when predicting which team will win the World Series this year there are 30 possible outcomes.
In these two examples one has 64 possible outcomes and one has 30 outcomes. Yet the 64 option tournament would be easier to predict.
Ticket #: 2364593
Jan 19 03:00 PM
Jan 19 06:30 PMNFL
NFLPARLAY (2 TEAMS)
[302] TOTAL u56-110
(NEW ENGLAND vrs DENVER)
[303] TOTAL o39-110
(SAN FRANCISCO vrs SEATTLE)50.00 / 130.00 130.00 WIN
WIN
WIN01/13/2014 03:13 PM Ticket #: 2370085
Jan 19 03:00 PM
Jan 19 06:30 PMNFL
NFLPARLAY (2 TEAMS)
[302] DENVER -250
[304] SEATTLE -195100.00 / 111.79 111.79 WIN
WIN
WIN01/18/2014 10:04 AM
Dont no what ur looking at but I see three posters above that hit it. A push on the 40 would most likely count as a win or tie and u would just get a payout on a 5 teamer.
I went 3-2-1, meh. 6 teamers are possible, I do them all the time, bigger BR swings, but they do hit.
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