View Poll Results: How often do you buy onto the 7?

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  • Always

    1 4.55%
  • Never

    16 72.73%
  • Sometimes (Please Explain your theory)

    5 22.73%
  1. #36
    chaka
    chaka's Avatar Become A Pro!
    Join Date: 12-29-09
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    I think this is a good example of stats being very misleading

    66 occurences w/final score difference of 7 happened about 8% of the time (66/800) but to really find how it applies to this situation you would need to :

    1)eliminate all games where the dog won by 7 from the 66(dog ML winner means the 1/2 pt wasnt factor)
    2)plus eliminate all games where the closing point spread wasnt 7 from the 66(0, -1,-2,-3 ,-4,-5,-6,-8+)

    leaving you just the games where the -7 pt fav won by 7- i am guessing there would only be a couple instances of this or "X"

    3) find the total number of games with pt spreads of -7 for the yr

    Then divide "x"(# times -7 fav won by 7) /number of all games with spread of -7

    if there were 3 times -7Fav won by 7 and 80 of the 800 games had spread of -7
    3/80= 3.75% odds of occurrence

    if it were 5x out of 60 games 5/60=8.3%
    the actual numbers are probably closer to 2/35=5.7% or less

    if 8% of all games randomly fall on 7, one would expect a specific event of -7 falling on 7 to occur at much lower rate

  2. #37
    KiDBaZkiT
    September 2021 POTM
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    Join Date: 10-20-09
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    I always buy the hook in my favor regardless.

  3. #38
    benjy
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    Join Date: 02-19-09
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    Quote Originally Posted by chaka View Post
    I think this is a good example of stats being very misleading

    66 occurences w/final score difference of 7 happened about 8% of the time (66/800) but to really find how it applies to this situation you would need to :

    1)eliminate all games where the dog won by 7 from the 66(dog ML winner means the 1/2 pt wasnt factor)
    2)plus eliminate all games where the closing point spread wasnt 7 from the 66(0, -1,-2,-3 ,-4,-5,-6,-8+)

    leaving you just the games where the -7 pt fav won by 7- i am guessing there would only be a couple instances of this or "X"

    3) find the total number of games with pt spreads of -7 for the yr

    Then divide "x"(# times -7 fav won by 7) /number of all games with spread of -7

    if there were 3 times -7Fav won by 7 and 80 of the 800 games had spread of -7
    3/80= 3.75% odds of occurrence

    if it were 5x out of 60 games 5/60=8.3%
    the actual numbers are probably closer to 2/35=5.7% or less

    if 8% of all games randomly fall on 7, one would expect a specific event of -7 falling on 7 to occur at much lower rate
    Nice first post!

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