Using Binomdist to find confidence %

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  • RicoJay13
    SBR Rookie
    • 03-14-11
    • 8

    #1
    Using Binomdist to find confidence %
    I'm trying to find out the confidence interval for my sample of win/loss picks. I've read a few books that mention using binomdist function and how to calculate excess wins and standard error, but I'm still not where I want to be with a definitive number. Right now I have this data:

    Std Error: 42.5
    Excess Wins: 43.3

    I've read that to have 95% confidence you need 2 standard errors, which would be 85 excess wins so I don't have that. But I do barely have the 68% confidence you get from 1 standard error. Correct right?

    And what about using binomdist function? I guess I just don't understand what the resulting % means to me. Binomdist(#wins, #samples, X, TRUE) yields a % result. I'm lost on what to enter for "X" and what that then means in the resulting % result. I read that if you enter the breakeven money win% for "X", say 52.4% for -110 vig lines, you get a resulting % of how often a random sample hits less than the breakeven 52.4%. But I'm still lost as to what that really means. Am I looking for a result that says 99.9%, ie does a higher resulting % mean more confidence? Is it the actual confidence interval? For my data, using the breakeven excess wins winrate yields a binomdist resulting % of 99.9%, seemingly proving I can be super confidence that I'm better than breakeven. But again, above we show I only have 68% based on the excess wins figures.

    Help is appreciated.
    Last edited by RicoJay13; 07-11-11, 10:31 AM.
  • bztips
    SBR Sharp
    • 06-03-10
    • 283

    #2
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