I knew how to do this a while back but have forgotten:
Say you have 3 teams who all have a 60% chance of winning.
-What is the probability of at least 1 of them winning?
-How about the probability of at least 2 of them winning?
I know the probability of all 3 of them winning would be .6*.6*.6 = 21.6%, but I forgot how to calculate the "either/or" probabilities.
Thanks!