[Sledge187]

I've been gambling for 15 years and still haven't taken the time to learn this game.

[Brock Landers]

you ALWAYS bet the odds behind the passline, BEST bet in the house

[BIGDAY]

Huck dice down a table and yell a lot.

[thunderous]

I've been gambling for 15 years and still haven't taken the time to learn this game.

Same here...never bothered to learn craps, been gambling for over 20 years...guess I love cards so much that a game without cards not appealing enough

[VegasInsider]

Same. No idea how to play. People have told me that you can win a lot quickly but also lose alot quickly.

Pass.

[allabout the $$$]

once you get into it there is no other casino game that compares to it

[stuler]

Craps more addicting than crack!!!!!Only game to play at any casino

[James D]

Ok here if goes....

You place a bet on the pass line. Let's say 5 dollars.
The shooter rolls.... If it's a 7 or 11 you win 5 dollars.....if it's a 2,3 or 12 you lose 5 dollars.
If 2,3,7, 11, or 12 happened as described above the betting is over. You either won 5 bucks or lost 5 bucks

If any other number comes up 4/5/6/8/9/10/11 that becomes your point.
Your five dollars remains in action and now you bet behind it. Most places let you bet 2x,3x or 5x your original 5 dollar bet. For our argument we will say 5x is allowed, it does vary though. This second bet goes directly behind your initial bet. That bet behind the five dollars is the best bet in the casino and you should always bet the maximum. That bet is paid the true mathematical odds by the casino.
lets say your point is a 10, that's a toughie. Because 10 is a hard number to roll with 2 dice. So now you only have one enemy, that is the number seven. If seven comes out you lose all the money your 5 dollar bet and the 25 you placed behind it. However if a ten comes you win 5 dollars on your original 5 dollar bet and 50 on the 25 you bet behind the 5. So your 30 risked won you 55. Now better is over and it all starts again.
In this instance you only bet the pass line and the number (10) so you were just hoping for a ten and against a seven. No other number mattered. Every other number that comes up they just pay people that made side bets or take money from the losers of the side bets. Those rolls mean nothing to you, you are only rooting for a 10 and against a seven......

here are the payouts depending on what number came up assuming your ten did not on your 5&25 wager

4 or 10. Pays 55. (5 and 50). 2-1
5 or 9. Pays 42.50. (5 and 37.50) 7 1/2 to 5
6 or 8. Pays 35. ( 5 and 30). 6-5

the 2-1 odds on 4/10 the 7.5-5 odds on 5/9 and the 6-5 odds on 6/8 are "true odds" like flipping a coin at even money. The house makes its casino edge in this game on the original 5 dollars where it only pays you even money despite you being a significant underdog.

Will explain more exotic bets in next post if you like

[kyhawk]

Best idea is just to google play craps online. The game centers around 7. It is the easiest number to hit. then its 6 0r 8,5-9, 4-10. Bet on the pass line to start. That means you only want 7 or 11 on first roll. I.e. you bet pass. player rolls 4. the number for you to win is 4.
If you roll 7 before 4 you lose. You want to take odds of the 4. That means putting stack behind the four, then you get 2-1 odds when you hit 4...if you hit it before 7. Don't be an idiot like me an bet big 6 or big 8, when I started and don't get odds.
There are all sorts of strategys. Just bet pass to start. Then bet on come line..next. Stay only with pass and two come bets. That is it.
It is a fast game. Betting pass is one of the lowest returns for a casino. Lot's of fun if a table gets hot.

http://entertainment.howstuffworks.c...ing-craps1.htm

Try http://wizardofodds.com/play/craps/v2/

[James D]

Ok seems like a few people posted ITT so I will add some more info...

let's say your point is ten like previously described but you want some more action. You can bet a bunch of exotic bets. The most common is basically betting the field by adding these bets . That means you have you .....

5 pass line
25 point. ( the ten). 2-1 ( 55.00 and your 30 is returned the roll is over)
25 on four. 2-1. (50.00)
25 on five 7 1/2 to 5. (37.50)
25.on Six 6-5. (30.00)
25. On Eight. 6-5. (30.00)
25. On Nine 7 1/2 to 5. (37.50 )

You added the five bets below the number ten so now you have tons of action! You pay like a one dollar commission on each of these bets . Every time anyone of those numbers 4/5/6/8/9 comes up you get paid at the odds and amount listed. If a ten comes you get paid what's listed above and the action is done and we start over. if a seven comes you lose all the money wagered which in this case is 155 dollars.

If you get at a table and play the board like this and the shooter throws a bunch of numbers before the 10 or 7 you can make a ton of money. Also you can pull the money off or increase it anytime you like. the only money you can not pull off is the original 5 dollars. That rides till it doubles up or goes to the house.

other bets like hard 8 or hard 6 are very simple. They are one roll bets, if you bet hard 8 you have one shot. Of shooter rolls 4-4 you get 30-1 . If not you lose. Odds against are 35-1, these type of bets are the worst in craps and are the ones the stickman yells the most to encourage action on them. They are like teasers or parlays to sports bettors

[No coincidences]

Where's the skill?

[allabout the $$$]

on the four and ten you get 49 for 25

[freeVICK]

max odds

[Brock Landers]

Where's the skill?

knowing when to turn off bets and when to maximize them

[James D]

on the four and ten you get 49 for 25

No you don't.

The point was ten so you get 50 not 49
on the 4 I said specifically you have to pay a dollar for this bet in my post so you 50-1 is 49

[Cuse0323]

hurts my head trying to learn, too dumb for craps.

[TheMoneyShot]

Would love to learn craps. What are some of the basic plays to get some action without losing a huge bankroll at the table? Something that's simple... so I can get some rhythm down. Don't understand the term betting for the shooter and betting against the shooter? What needs to happen? And how many rolls of the dice do you get until it happens?

[VegasInsider]

This is fun. I started goofing around on it tonight

http://espn.go.com/free-online-games..._/gid/18/craps

[James D]

hurts my head trying to learn, too dumb for craps.

I wrote it long form to make it real simple. If you just play the point and the odds which is my first post, it is really simple. The other stuff is slightly more complex

moneyshot,

the first post is " craps for beginners " it's this easy....

1. Bet 5 bucks root for 7 or 11 where you win 5 and against 2,3, or 12 which is where you lose 5.......
2. If any other number comes up 4/5/6/8/9/10 that becomes your point..
3. Bet another 25 hoping that number (4/5/6/8/9/10) comes again before a 7 if it does you win between 36 and 55 depending on the number, if the seven comes up you lose the 30 you invested. Any other numbers that come up before your point or the dreaded seven means nothing. Shooter just rolls again and again till your point or the seven ends the roll.

Thats it in a nutshell

[tony_come]

All in the wrists

[Cuse0323]

I wrote it long form to make it real simple. If you just play the point and the odds which is my first post, it is really simple. The other stuff is slightly more complex

I appreciate the write up, I understand it more than I ever have honestly after reading it. Still, it's something I just can't put my mind to, so many things going on at once.

[Cuse0323]

I feel like it's one of those things that just needs to click in your brain and then it's so simple. Like any math. All I see are numbers and words all over the place for now, if I put my mind to it I know I could learn it though.

[Brock Landers]

It looks like a lot going on at once

But in reality, it's one number at a time...all that matters.

[allabout the $$$]

No you don't.

The point was ten so you get 50 not 49
on the 4 I said specifically you have to pay a dollar for this bet in my post so you 50-1 is 49

your right wasnt thinking as 10 as the point my mistake

25 on four. 2-1. (50.00)

you dont say minus the 1 here you say it pays 2-1

[James D]

Many casinos in vegas have tried to do 100x odds. Casino royale had it just last year. Riviera, frontier, stratosphere , Binions I Remember a bunch of places trying it. Usually it's smaller casinos trying to get high rollers into their place. At 100x odds you need to bet a minimum of 505 per roll so most people can't do it. It's a dangerous move for casinos. The house edge is so so low it is virtually a coin flip.

Look how razor thin the house edge is on a 5 dollar bet max behind (500) so 505 wagered. The numbers listed are first the actually payout and then what the payout would be with true odds ( no house edge)

Point is 4 or 10 1005. 1010
point is 5 or 9 755. 757.50
point is 6 or 8 605. 606

look how thin the margin is for the house!! The only thing not factored here is the original five dollar role where you want a 7-11 and the house wants a 2,3,12. But in the initial roll you are actually a 2-1 favorite!! Yout of the 36 possible rolls you have 8 ways to roll a 7 or 11 and only 4 ways to roll the 2,3,12

[TankHankerous]

Its easier to understand the concept while looking at the table. There are a few tutorials on youtube, here's one of them:

[James D]

your right wasnt thinking as 10 as the point my mistake


you dont say minus the 1 here you say it pays 2-1

I appreciate your catching the first mistake, but read the post where I list the extra field bets . In the second sentence I say " you have to pay a dollar commission for each of these bets"" so the 50-1 is 49

[TheMoneyShot]

I wrote it long form to make it real simple. If you just play the point and the odds which is my first post, it is really simple. The other stuff is slightly more complex

moneyshot,

the first post is " craps for beginners " it's this easy....

1. Bet 5 bucks root for 7 or 11 where you win 5 and against 2,3, or 12 which is where you lose 5.......
2. If any other number comes up 4/5/6/8/9/10 that becomes your point..
3. Bet another 25 hoping that number (4/5/6/8/9/10) comes again before a 7 if it does you win between 36 and 55 depending on the number, if the seven comes up you lose the 30 you invested. Any other numbers that come up before your point or the dreaded seven means nothing. Shooter just rolls again and again till your point or the seven ends the roll.

Thats it in a nutshell

Thanks James. Let me see if I understand you correctly.

I get to the table. And before the first roll is out. I lay $5 on if 7 or 11 hits before 2, 3, or 12 does.

If another number comes out then I lay $25 on (4/5/6/8/9/10) before a 7 hits. (What do you call this on the table? Pass line or something?

Why do I lose the initial $5 on the 7 or 11? I thought I needed it to land on 7 or 11?

[las8]

Where's the skill?

it's called dice setting

[allabout the $$$]

I appreciate your catching the first mistake, but read the post where I list the extra field bets . In the second sentence I say " you have to pay a dollar commission for each of these bets"" so the 50-1 is 49

yes i see but that can be very misleading on the 6 and 8 because you pay the dollar one time you put 6 down as your bet to win 7 back where as with the other bets you are doing it every time on the 5 and 9 if you place a 10 bet you are dropping the one to get 15 back. on the 6 and 8 you lay the odds to get the even payout. just like on the 5 and 9 if they are the point you want to lay even odds if not you will lose money since the craps table doesnt use 2.50 chips

[kmarinouofm]

hit a seven when you are supposed to . .don't hit a seven when you aren't supposed to .. got it ?

[allabout the $$$]

Thanks James. Let me see if I understand you correctly.

I get to the table. And before the first roll is out. I lay $5 on if 7 or 11 hits before 2, 3, or 12 does.

If another number comes out then I lay $25 on (4/5/6/8/9/10) before a 7 hits. (What do you call this on the table? Pass line or something?

Why do I lose the initial $5 on the 7 or 11? I thought I needed it to land on 7 or 11?

because once that first number is thrown that is now what your pass line bet is for. since 7 is the easiest number mathematically to roll it is only good for the come out roll once your point is established you dont want to see a 7

[kevin101]

Ill just place a few bets and learn as the game goes on and if the casino hustles me then so be it. Seems like the easiest way to learn

[Trep]

Hardway basic sets ftw

[James D]

Thanks James. Let me see if I understand you correctly.

I get to the table. And before the first roll is out. I lay $5 on if 7 or 11 hits before 2, 3, or 12 does.

If another number comes out then I lay $25 on (4/5/6/8/9/10) before a 7 hits. (What do you call this on the table? Pass line or something?

Why do I lose the initial $5 on the 7 or 11? I thought I needed it to land on 7 or 11?

I never said you lose on 11.
7 is your friend on the first roll and your enemy afterwards.

Money you..

1. bet 5 bucks hoping for a 7 or 11 and against 2/3/12 if you get 7/11 winner! 2/3/12 loser! 5 bucks either way. If this happens you put another 5 up and start again

2. If a different number came 4/5/6/8/9/10 that 5 stays in action and you add 25... Now you have 30 at risk

3 whatever that different number in line 2 (4/5/6/8/9/ or 10) is now the only thing you want to see. The only thing you don't want to see is a seven. If your number from line 2 comes in you win between 35-55 bucks and get your 30 back. If the seven comes before your number you lose your 30.

4. Once we see your number from line 2 or the number seven the roll is over.